Select an activity that can be added to the schedule for the first day. Then select an activity that could be added to the schedule for the second day. Make only two selections, one in each column.
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Correct answer:
To solve this logic problem, first list the constraints:
- 12 hours = total hours available per day
- 4 hours = maximum hours for walking per day
- Minimum 4 art or architecture activities during the 2 days
- Maximum 1 art museum per day
- Minimum of 1 beach activity during the trip
- Minimum of 1 shopping activity each day
Now evaluate the activities the family has already planned to see which constraints are satisfied and which are not.
**Day 1:** The family has planned 11 hours of activities with 1 hour of walking. Therefore, only 1 hour remains, and a walking activity could be chosen if desired.
**Day 2:** The family has planned 10 hours of activities (3 + 2 + 4 + 1 = 10) with 4 hours of walking. This means that 2 hours remain for additional activities, but none can involve walking since the 4-hour walking limit has been reached.
Given these constraints, the only activities possible for each day are:
- **Day 1:** Mirador De Colon, Montserrat, or La Pedrera
- **Day 2:** Montserrat
Therefore, the family must choose the sightseeing trip to Montserrat on Day 2, leaving only Mirador De Colon and La Pedrera as options for Day 1.
Now consider the family preferences. Mom already has shopping on each day (Las Ramblas and Barri Gotico), and Little Brother has a beach activity on Day 2 (Nova Icària). However, Big Sister only has 3 of her required 4 art or architecture activities. Both Mirador De Colon and La Pedrera fit this category, but Dad will not go to more than 1 art exhibit on a single day, and the family will already visit Park Güell on Day 1. This means they cannot also visit La Pedrera. Therefore, the family will visit Mirador De Colon on Day 1.