SET Practice Questions
Master GMAT SET with comprehensive practice questions. Build your quantitative reasoning skills through detailed explanations and strategic practice.
Key Skills
- Problem Solving
- Analytical Thinking
- Mathematical Reasoning
- Strategic Analysis
Study Tips
- Focus on understanding SET concepts fundamentally
- Practice with timer to improve speed and accuracy
- Review explanations thoroughly to learn solution methods
- Identify common patterns and shortcuts for this topic
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View Explanation
Correct Answer: E
Of the films Empty Set Studios released last year, \(60\%\) were comedies and the rest were horror films.
$$\begin{array}{|c|c|c|c|} \hline & \text{Comedies} & \text{Horror Films} & \text{Total} \\ \hline \text{Profitable} & & & \\ \hline \text{Unprofitable} & & & \\ \hline \text{Total} & 0.6x & 0.4x & x \\ \hline \end{array}$$
\(75\%\) of the comedies were profitable, but \(75\%\) of the horror moves were unprofitable.
$$\begin{array}{|c|c|c|c|} \hline & \text{Comedies} & \text{Horror Films} & \text{Total} \\ \hline \text{Profitable} & 0.75(0.6x) & & \\ \hline \text{Unprofitable} & & 0.75(0.4x) & \\ \hline \text{Total} & 0.6x & 0.4x & x \\ \hline \end{array}$$
If the studio made a total of \(40\) films...
$$\begin{array}{|c|c|c|c|} \hline & \text{Comedies} & \text{Horror Films} & \text{Total} \\ \hline \text{Profitable} & 0.75(24) = 18 & & \\ \hline \text{Unprofitable} & & 0.75(16) = 12 & \\ \hline \text{Total} & 0.6(40) = 24 & 0.4(40) = 16 & x = 40 \\ \hline \end{array}$$
Since each row and each column must sum up to the Total value, we can fill in the remaining boxes
$$\begin{array}{|c|c|c|c|} \hline & \text{Comedies} & \text{Horror Films} & \text{Total} \\ \hline \text{Profitable} & 18 & 4 & 22 \\ \hline \text{Unprofitable} & 6 & 12 & 18 \\ \hline \text{Total} & 24 & 16 & 40 \\ \hline \end{array}$$ The problem seeks the total number of profitable films, which is 22.
The correct answer is E.
View Explanation
Correct Answer: C
View Explanation
Correct Answer: D
$$\begin{array}{|l|c|c|c|}\hline & \text{Supposed To Be On} & \text{Supposed To Be Off} & \text{TOTAL} \\\hline \text{Actually on} & & 0.4x & 80 \\\hline \text{Actually off} & 0.1(100 - x) & 0.6x & 20 \\\hline \text{TOTAL} & 100 - x & x & 100 \\\hline \end{array}$$
Using the relationships inherent in the matrix, we see that:
0.1(100 − x) + 0.6x = 20
10 − 0.1x + 0.6x = 20
0.5x = 10 so x = 20
We can now fill in the matrix with values:
$$\begin{array}{|l|c|c|c|}\hline & \text{Supposed To Be On} & \text{Supposed To Be Off} & \text{TOTAL} \\\hline \text{Actually on} & 72 & 8 & 80 \\\hline \text{Actually off} & 8 & 12 & 20 \\\hline \text{TOTAL} & 80 & 20 & 100 \\\hline \end{array}$$
Of the 80 lights that are actually on, 8, or \( 10\% \), are supposed to be off.
The correct answer is D.
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