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Coordinate Geometry Practice Questions

Practice Coordinate Geometry questions with worked explanations and timing guidance for Quantitative Reasoning.

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Question 1 of 5 Medium

In the figure shown, point \(P(-\sqrt{3}, 1)\) and \(Q(s, t)\) lie on the circle with center O. What is the value of \(s\)?

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Correct answer: B

As shown in the figure, OP and OQ are perpendicular radii of the circle with center O at the origin.<br><br>

The slope of line OP is \(-\frac{1}{\sqrt{3}}\).<br><br>

Since OP ⊥ OQ, their slopes are negative reciprocals. The slope of OQ is \(\frac{t}{s}\), so:<br>
\[\frac{t}{s} \times \left(-\frac{1}{\sqrt{3}}\right) = -1\]<br>
\[t = \sqrt{3}s\]<br><br>

Since OP is a radius: \(OP = \sqrt{(-\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = 2\)<br><br>

Since OQ = OP = 2: \(t^2 + s^2 = 4\)<br><br>

Substituting \(t = \sqrt{3}s\):<br>
\[(\sqrt{3}s)^2 + s^2 = 4\]<br>
\[3s^2 + s^2 = 4\]<br>
\[4s^2 = 4\]<br>
\[s^2 = 1\]<br>
\[s = \pm 1\]<br><br>

Since point Q is shown in the first quadrant in the figure (where both coordinates are positive), \(s = 1\).<br><br>

The answer is B.

Question 2 of 5 Medium

For any triangle \( T \) in the xy-coordinate plane, the center of \( T \) is defined to be the point whose x-coordinate is the average (arithmetic mean) of the x-coordinates of the vertices of \( T \) and whose y-coordinate is the average of the y-coordinates of the vertices of \( T \). If a certain triangle has vertices at the points \( (0,0) \) and \( (6,0) \) and center at the point \( (3,2) \), what are the coordinates of the remaining vertex?

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Correct answer: B

Let the third vertex be \( (x, y) \).<br>Center x:<br>$$ \frac{0 + 6 + x}{3} = 3 \implies 6 + x = 9 \implies x = 3 $$<br>Center y:<br>$$ \frac{0 + 0 + y}{3} = 2 \implies y = 6 $$<br>Vertex is \( (3, 6) \).<br>The correct answer is B.

Question 3 of 5 Medium

In the xy-plane, line \( k \) has positive slope and x-intercept 4. If the area of the triangle formed by line \( k \) and the two axes is 12, what is the y-intercept of line \( k \)?

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Correct answer: A

Triangle vertices are \( (0,0) \), \( (4,0) \), and \( (0,y) \).<br>Area:<br>$$ \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 4 \times |y| = 2|y| $$<br>$$ 2|y| = 12 \implies |y| = 6 $$<br>Slope:<br>$$ \frac{y-0}{0-4} = -\frac{y}{4} $$<br>Since slope is positive, \( -\frac{y}{4} > 0 \implies y < 0 \).<br>So \( y = -6 \).<br>The correct answer is A.

Question 4 of 5 Medium

Line \( l \) is defined by the equation \( y - 5x = 4 \) and line \( w \) is defined by the equation \( 10y + 2x + 20 = 0 \). If line \( k \) does not intersect line \( l \), what is the degree measure of the angle formed by line \( k \) and line \( w \)?

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Question 5 of 5 Medium

In the rectangular coordinate plane, points \( X \) and \( Z \) lie on the same line through the origin and points \( W \) and \( Y \) lie on the same line through the origin. If \( a^2 + b^2 = c^2 + d^2 \) and \( e^2 + f^2 = g^2 + h^2 \), what is the value of length \( XZ - WY \)?

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