CGM Practice Questions
Master GMAT CGM with comprehensive practice questions. Build your quantitative reasoning skills through detailed explanations and strategic practice.
Key Skills
- Problem Solving
- Analytical Thinking
- Mathematical Reasoning
- Strategic Analysis
Study Tips
- Focus on understanding CGM concepts fundamentally
- Practice with timer to improve speed and accuracy
- Review explanations thoroughly to learn solution methods
- Identify common patterns and shortcuts for this topic
Free Preview: Try 3 questions below. Sign up free to access all 19 questions.
View Explanation
Correct Answer: B
slope of OQ is \(\frac{t}{s}\), so \(\frac{t}{s} \times \left(-\frac{1}{\sqrt{3}}\right) = -1\), \(t = \sqrt{3}s\)
\(OQ = OP = 2\), \(t^2 + s^2 = 4\). Combined above, \(s = \pm 1 \Rightarrow s = 1\)
Answer is B
View Explanation
Correct Answer: B
Center x:
$$ \frac{0 + 6 + x}{3} = 3 \implies 6 + x = 9 \implies x = 3 $$
Center y:
$$ \frac{0 + 0 + y}{3} = 2 \implies y = 6 $$
Vertex is \( (3, 6) \).
The correct answer is B.
View Explanation
Correct Answer: A
Area:
$$ \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 4 \times |y| = 2|y| $$
$$ 2|y| = 12 \implies |y| = 6 $$
Slope:
$$ \frac{y-0}{0-4} = -\frac{y}{4} $$
Since slope is positive, \( -\frac{y}{4} > 0 \implies y < 0 \).
So \( y = -6 \).
The correct answer is A.
Ready for more practice?
Access 19 CGM questions plus thousands more across all GMAT topics