Inequalities Absolute Practice Questions
Master GMAT Inequalities Absolute with comprehensive practice questions. Build your quantitative reasoning skills through detailed explanations and strategic practice.
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Correct Answer: E
\( 3|3 - x| = 7 \)
\( |3 - x| = \frac{7}{3} \)
When removing the absolute value bars, we need to keep in mind that the expression inside the absolute value bars \( (3 - x) \) could be positive or negative. Let's consider both possibilities:
When \( (3 - x) \) is positive:
\( (3 - x) = \frac{7}{3} \)
\( 3 - \frac{7}{3} = x \)
\( \frac{9}{3} - \frac{7}{3} = x \)
\( x = \frac{2}{3} \)
When \( (3 - x) \) is negative:
\( -(3 - x) = \frac{7}{3} \)
\( x - 3 = \frac{7}{3} \)
\( x = \frac{7}{3} + 3 \)
\( x = \frac{7}{3} + \frac{9}{3} \)
\( x = \frac{16}{3} \)
So, the two possible values for \( x \) are \( \frac{2}{3} \) and \( \frac{16}{3} \). The product of these values is \( \frac{32}{9} \).
The correct answer is E.
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Correct Answer: D
We can list the possible sums:
$$\begin{array}{|c|c|c|} \hline a & b & a+b \\ \hline \frac{1}{3} & \frac{2}{3} & 1 \\ \hline \frac{1}{3} & -\frac{2}{3} & -\frac{1}{3} \\ \hline -\frac{1}{3} & \frac{2}{3} & \frac{1}{3} \\ \hline -\frac{1}{3} & -\frac{2}{3} & -1 \\ \hline \end{array}$$
Comparing with the options, \( \frac{2}{3} \) is NOT a possible sum.
The correct answer is D.
View Explanation
Correct Answer: A
This yields two cases:
\( x + 4 = 3 \implies x = -1 \)
\( x + 4 = -3 \implies x = -7 \)
The question asks for the value of \( x - 4 \), not \( x \) itself. Calculate \( x - 4 \) for both solutions:
If \( x = -1 \): \( x - 4 = -1 - 4 = -5 \) (not among the answer choices).
If \( x = -7 \): \( x - 4 = -7 - 4 = -11 \).
Since \( -11 \) is the only value that appears among the answer choices, the correct answer is A.